A. Required Remainder

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given three integers x,yx,y and nn. Your task is to find the maximum integer kk such that 0≤k≤n0≤k≤n that kmodx=ykmodx=y, where modmod is modulo operation. Many programming languages use percent operator % to implement it.

In other words, with given x,yx,y and nn you need to find the maximum possible integer from 00 to nn that has the remainder yy modulo xx.

You have to answer tt independent test cases. It is guaranteed that such kk exists for each test case.

Input

The first line of the input contains one integer tt (1≤t≤5⋅1041≤t≤5⋅104) — the number of test cases. The next tt lines contain test cases.

The only line of the test case contains three integers x,yx,y and nn (2≤x≤109; 0≤y<x; y≤n≤1092≤x≤109; 0≤y<x; y≤n≤109).

It can be shown that such kk always exists under the given constraints.

Output

For each test case, print the answer — maximum non-negative integer kk such that 0≤k≤n0≤k≤n and kmodx=ykmodx=y. It is guaranteed that the answer always exists.

Example

input

Copy

7
7 5 12345
5 0 4
10 5 15
17 8 54321
499999993 9 1000000000
10 5 187
2 0 999999999

output

Copy

12339
0
15
54306
999999995
185
999999998

Note

In the first test case of the example, the answer is 12339=7⋅1762+512339=7⋅1762+5 (thus, 12339mod7=512339mod7=5). It is obvious that there is no greater integer not exceeding 1234512345 which has the remainder 55 modulo 77.

 

解題說明:水題,直接構造即可。

#include<stdio.h>

int main()
{
	int t, x, y, n;
	scanf("%d", &t);
	while (t--)
	{
		scanf("%d%d%d", &x, &y, &n);
		printf("%d\n", ((n - y) / x)*x + y);
	}
	return 0;
}

 

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