mysql的sqlyog學習筆記(代碼用命令行顯示 )

語言

DQL(data query language)(數據 查詢 語言)
SQL(s=select)(選擇 查詢 語言)
DML(data manipulation language)(數據 操作 語言)
DDL(data define language)(數據定義語言)
TCL(transaction control language)(事務控制語言)



查詢

基礎查詢

select 查詢列表 from 表名;

特點:查詢的結果集 是一個虛擬表(打印內容)

select後面跟的查詢列表,可以有多個部分組成,中間用逗號隔開:select 字段1,字段2,表達式 from 表;

執行順序
① from子句
② select子句

查詢列表可以是:字段、表達式、常量、函數等
USE myemployees;

一、查詢常量
SELECT 100 ;

二、查詢表達式
SELECT 100%3;

三、查詢單個字段
SELECT last_name FROM employees;

四、查詢多個字段
SELECT last_name,email,employee_id FROM employees;

五、查詢所有字段
SELECT * FROM employees;

查詢函數(調用函數,獲取返回值)

SELECT DATABASE();
SELECT VERSION();
SELECT USER();

起別名

方式一:使用as關鍵字
SELECT USER() AS 用戶名;
SELECT USER() AS “用戶名”;
SELECT USER() AS ‘用戶名’;


SELECT last_name AS “姓 名” FROM employees;

方式二:使用空格
SELECT USER() 用戶名;
SELECT USER() “用戶名”;
SELECT USER() ‘用戶名’;


SELECT last_name “姓 名” FROM employees;

mysql> select last_name as 'xing ming' from employees;
+-------------+
| xing ming   |
+-------------+
| K_ing       |
| Kochhar     |
| De Haan     |
| Hunold      |

+的作用

-需求:查詢 first_name 和last_name 拼接成的全名,最終起別名爲:姓 名

方案1:使用+ pass×
SELECT first_name+last_name AS “姓 名”
FROM employees;

方案2:使用concat拼接函數
SELECT CONCAT(first_name,last_name) AS “姓 名”
FROM employees;

mysql> select concat(first_name,last_name) as 'xing ming' from employees;
+------------------+
| xing ming        |
+------------------+
| StevenK_ing      |
| NeenaKochhar     |
| LexDe Haan       |
| AlexanderHunold  |
| BruceErnst       |
| DavidAustin      |
| ValliPataballa   |
| DianaLorentz     |
| NancyGreenberg   |

distinct的使用(去重)

mysql> select department_id from employees;  #有重複
+---------------+
| department_id |
+---------------+
|          NULL |
|            10 |
|            20 |
|            20 |
|            30 |
|            30 |
|            30 |
|            30 |
|            30 |
|            30 |

distinct adj. 明顯的;獨特的;清楚的;有區別的
查詢員工涉及到的部門編號有哪些
SELECT DISTINCT department_id FROM employees;

mysql> select distinct department_id from employees; #無重複
+---------------+
| department_id |
+---------------+
|          NULL |
|            10 |
|            20 |
|            30 |
|            40 |
|            50 |
|            60 |
|            70 |
|            80 |
|            90 |
|           100 |
|           110 |
+---------------+
12 rows in set (0.00 sec)

查看錶的結構

DESC employees;

列 columns
SHOW COLUMNS FROM employees;

條件查詢

select 查詢列表
from 表名
where 篩選條件;

執行順序:
①from子句
②where子句
③select子句


select last_name,first_name from employees where salary>20000;

按關係表達式篩選

關係運算符:> < >= <= = <> (或 != )(不等於)

mysql> select *                          #要查的東西
    -> from employees                    #表名
    -> where department_id <> 100;       #條件
+-------------+-------------+-------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
| employee_id | first_name  | last_name   | email    | phone_number       | job_id     | salary   | commission_pct | manager_id | department_id | hiredate            |
+-------------+-------------+-------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
|         100 | Steven      | K_ing       | SKING    | 515.123.4567       | AD_PRES    | 24000.00 |           NULL |       NULL |            90 | 1992-04-03 00:00:00 |
|         101 | Neena       | Kochhar     | NKOCHHAR | 515.123.4568       | AD_VP      | 17000.00 |           NULL |        100 |            90 | 1992-04-03 00:00:00 |
|         102 | Lex         | De Haan     | LDEHAAN  | 515.123.4569       | AD_VP      | 17000.00 |           NULL |        100 |            90 | 1992-04-03 00:00:00 |
|         103 | Alexander   | Hunold      | AHUNOLD  | 590.423.4567       | IT_PROG    |  9000.00 |           NULL |        102 |            60 | 1992-04-03 00:00:00 |
|         104 | Bruce       | Ernst       | BERNST   | 590.423.4568       | IT_PROG    |  6000.00 |           NULL |        103 |            60 | 1992-04-03 00:00:00 |
|         105 | David       | Austin      | DAUSTIN  | 590.423.4569       | IT_PROG    |  4800.00 |           NULL |        103 |            60 | 1998-03-03 00:00:00 |
|         106 | Valli       | Pataballa   | VPATABAL | 590.423.4560       | IT_PROG    |  4800.00 |           NULL |        103 |            60 | 1998-03-03 00:00:00 |
|         107 | Diana       | Lorentz     | DLORENTZ | 590.423.5567       | IT_PROG    |  4200.00 |           NULL |        103 |            60 | 1998-03-03 00:00:00 |
|         114 | Den         | Raphaely    | DRAPHEAL | 515.127.4561       | PU_MAN     | 11000.00 |           NULL |        100 |            30 | 2000-09-09 00:00:00 |
|         115 | Alexander   | Khoo        | AKHOO    | 515.127.4562       | PU_CLERK   |  3100.00 |           NULL |        114 |            30 | 2000-09-09 00:00:00 |
|         116 | Shelli      | Baida       | SBAIDA   | 515.127.4563       | PU_CLERK   |  2900.00 |           NULL |        114 |            30 | 2000-09-09 00:00:00 |
|         117 | Sigal       | Tobias      | STOBIAS  | 515.127.4564       | PU_CLERK   |  2800.00 |           NULL |        114 |            30 | 2000-09-09 00:00:00 |
|         118 | Guy         | Himuro      | GHIMURO  | 515.127.4565       | PU_CLERK   |  2600.00 |           NULL |    

案例2:查詢工資<15000的姓名、工資

mysql> select last_name,salary  #要查的東西
    -> from employees           #表名
    -> where salary<15000;      #篩選條件
+-------------+----------+
| last_name   | salary   |
+-------------+----------+
| Hunold      |  9000.00 |
| Ernst       |  6000.00 |
| Austin      |  4800.00 |

按邏輯表達式篩選

邏輯運算符:and or not 也可以使用&& || !

案例:查詢獎金率>0.03 或者 員工編號在60-110之間的員工信息

mysql> select *
    -> from employees
    -> where commission_pct >0.03 or(employee_id >=60 and employee_id<=110);
+-------------+-------------+------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
| employee_id | first_name  | last_name  | email    | phone_number       | job_id     | salary   | commission_pct | manager_id | department_id | hiredate            |
+-------------+-------------+------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
|         100 | Steven      | K_ing      | SKING    | 515.123.4567       | AD_PRES    | 24000.00 |           NULL |       NULL |            90 | 1992-04-03 00:00:00 |
|         101 | Neena       | Kochhar    | NKOCHHAR | 515.123.4568       | AD_VP      | 17000.00 |           NULL |        100 |            90 | 1992-04-03 00:00:00 |
|         102 | Lex         | De Haan    | LDEHAAN  | 515.123.4569       | AD_VP      | 17000.00 |           NULL |        100 |            90 | 1992-04-03 00:00:00 |
|         103 | Alexander 

模糊查詢

like

功能:一般和通配符搭配使用,對字符型數據進行部分匹配查詢
常見的通配符:
_ 任意單個字符
% 任意多個字符,支持0-多個
like/not like



案例1:查詢姓名中包含字符a的員工信息

mysql> select *
    -> from employees
    -> where last_name like '%a%';
+-------------+-------------+------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
| employee_id | first_name  | last_name  | email    | phone_number       | job_id     | salary   | commission_pct | manager_id | department_id | hiredate            |
+-------------+-------------+------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
|         101 | Neena       | Kochhar    | NKOCHHAR | 515.123.4568       | AD_VP      | 17000.00 |           NULL |        100 |            90 | 1992-04-03 00:00:00 |
|         102 | Lex         | De Haan    | LDEHAAN  | 515.123.4569       | AD_VP      | 17000.00 |           NULL |        100 |            90 | 1992-04-03 00:00:00 |
|         105 | David       | Austin     | DAUSTIN  | 590.423.4569       | IT_PROG    |  4800.00 |           NULL |        103 |

案例2:查詢姓名中包含第三個字符爲x的員工信息

mysql> select *
    -> from employees
    -> where last_name like '__x%';
+-------------+------------+-----------+-------+--------------------+--------+---------+----------------+------------+---------------+---------------------+
| employee_id | first_name | last_name | email | phone_number       | job_id | salary  | commission_pct | manager_id | department_id | hiredate            |
+-------------+------------+-----------+-------+--------------------+--------+---------+----------------+------------+---------------+---------------------+
|         170 | Tayler     | Fox       | TFOX  | 011.44.1343.729268 | SA_REP | 9600.00 |           0.20 |        148 |            80 | 2014-03-05 00:00:00 |
+-------------+------------+-----------+-------+--------------------+--------+---------+----------------+------------+---------------+---------------------+
1 row in set (0.00 sec)

案例3:查詢姓名中包含第二個字符爲_的員工信息

mysql> select *
    -> from employees
    -> where last_name like '_\_%';
+-------------+------------+-----------+-------+--------------------+---------+----------+----------------+------------+---------------+---------------------+
| employee_id | first_name | last_name | email | phone_number       | job_id  | salary   | commission_pct | manager_id | department_id | hiredate            |
+-------------+------------+-----------+-------+--------------------+---------+----------+----------------+------------+---------------+---------------------+
|         100 | Steven     | K_ing     | SKING | 515.123.4567       | AD_PRES | 24000.00 |           NULL |       NULL |            90 | 1992-04-03 00:00:00 |
|         156 | Janette    | K_ing     | JKING | 011.44.1345.429268 | SA_REP  | 10000.00 |           0.35 |        146 |            80 | 2014-03-05 00:00:00 |
+-------------+------------+-----------+-------+--------------------+---------+----------+----------------+------------+---------------+---------------------+
2 rows in set (0.00 sec)
SELECT *
FROM employees
WHERE last_name LIKE '_$_%' ESCAPE '$'; #將¥定義爲轉義字符

escape
vt. 逃避,避開,避免;被忘掉;被忽視
vi. 逃脫;避開;溜走;

in

查詢某字段的值是否屬於指定的列表之內
a in(常量值1,常量值2,常量值3,…)
a not in(常量值1,常量值2,常量值3,…)

in/not in

案例1:查詢部門編號是30/50/90的員工名、部門編號

#方式1:
SELECT last_name,department_id
FROM employees
WHERE department_id IN(30,50,90);

#方式2:

SELECT last_name,department_id
FROM employees
WHERE department_id = 30
OR department_id = 50
OR department_id = 90;

案例2:查詢工種編號不是SH_CLERK或IT_PROG的員工信息

#方式1:
SELECT *
FROM employees
WHERE job_id NOT IN('SH_CLERK','IT_PROG');

#方式2:
SELECT *
FROM employees
WHERE NOT(job_id ='SH_CLERK'
OR job_id = 'IT_PROG');
mysql> select *
    -> from employees
    -> where not(job_id ='SH_CLERK'
    -> or job_id ='IT_PROG');
+-------------+-------------+-------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
| employee_id | first_name  | last_name   | email    | phone_number       | job_id     | salary   | commission_pct | manager_id | department_id | hiredate            |
+-------------+-------------+-------------+----------+--------------------+------------+----------+----------------+------------+---------------+---------------------+
|         100 | Steven      | K_ing       | SKING    | 515.123.4567       | AD_PRES    | 24000.00 |           NULL |       NULL |            90 | 1992-04-03 00:00:00 |
|         101 | Neena       | Kochhar     | NKOCHHAR | 515.123.4568       | AD_VP      | 17000.00 |           NULL |        100 |            90 | 1992-04-03 00:00:00 |
|         10

between and

判斷某個字段的值是否介於xx之間
between and/not between and

案例1:查詢部門編號是30-90之間的部門編號、員工姓名

#方式1:
SELECT department_id,last_name
FROM employees
WHERE department_id BETWEEN 30 AND 90;

#方式2:

SELECT department_id,last_name
FROM employees
WHERE department_id>=30 AND department_id<=90;

案例2:查詢年薪不是100000-200000之間的員工姓名、工資、年薪

SELECT last_name,salary,salary*12*(1+IFNULL(commission_pct,0)) 年薪
FROM employees
WHERE salary*12*(1+IFNULL(commission_pct,0))<100000 OR salary*12*(1+IFNULL(commission_pct,0))>200000;



SELECT last_name,salary,salary*12*(1+IFNULL(commission_pct,0)) 年薪
FROM employees
WHERE salary*12*(1+IFNULL(commission_pct,0)) NOT BETWEEN 100000 AND 200000;
mysql> SELECT last_name,salary,salary*12*(1+IFNULL(commission_pct,0))
    -> from employees
    -> WHERE salary*12*(1+IFNULL(commission_pct,0)) NOT BETWEEN 100000 AND 200000;
+-------------+----------+----------------------------------------+
| last_name   | salary   | salary*12*(1+IFNULL(commission_pct,0)) |
+-------------+----------+----------------------------------------+
| K_ing       | 24000.00 |                              288000.00 |
| Kochhar     | 17000.00 |                              204000.00 |
| De Haan     | 17000.00 |                              204000.00 |
| Ernst       |  6000.00 |                               72000.00 |
| Austin      |  4800.00 |                               57600.00 |

is null

案例1:查詢沒有獎金的員工信息
SELECT *
FROM employees
WHERE commission_pct IS NULL;
案例2:查詢有獎金的員工信息
SELECT *
FROM employees
WHERE commission_pct IS NOT NULL;

= 只能判斷普通的內容

IS 只能判斷NULL值

<=> 安全等於,既能判斷普通內容,又能判斷NULL值

SELECT *
FROM employees
WHERE salary <=> 10000;

SELECT *
FROM employees
WHERE commission_pct <=> NULL;
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