In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki...
One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.
Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (1<N≤1,000), the number of keys in the tree. Then the next line contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.
Finally print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all.
Sample Input 1:
8
98 72 86 60 65 12 23 50
Sample Output 1:
98 86 23
98 86 12
98 72 65
98 72 60 50
Max Heap
Sample Input 2:
8
8 38 25 58 52 82 70 60
Sample Output 2:
8 25 70
8 25 82
8 38 52
8 38 58 60
Min Heap
Sample Input 3:
8
10 28 15 12 34 9 8 56
Sample Output 3:
10 15 8
10 15 9
10 28 34
10 28 12 56
Not Heap
題目重點信息提取：1.輸入：positive integer N正整數， N distinct integer keys，N個互不相等 的整數
給出一顆完全二叉樹 **level order** traversal sequence of a **complete binary tree**
提取重點翻譯：level order 與 complete binary tree ，input一個完全二叉樹的層序遍歷序列
2.輸出： 重點翻譯：first print **all the paths from the root to the leaves**
先打印出所有從根結點到葉子結點的路徑，all the paths in its **right subtree** must be printed **before** those in its **left subtree**，到右子樹的路徑要先於到左子樹路徑打印。
畫圖對應樣例的輸入輸出也可以快速判斷出來
思路：深度遍歷並打印出所有的路徑（先右後左），用vector存儲路徑上的所有結點，通過push和pop回溯，維護路徑，關於 index <= n ，由於是先右後左，需要對只有左葉子結點而無右葉子結點的點進行特判。
#include <iostream>
#include <stdio.h>
#include <vector>
using namespace std;
int n,a[1001],isMaxHeap = 1,isMinHeap = 1;
vector<int> v;
void R_dfs(int index){ //從右至左的深度優先遍歷
if(index * 2 > n && index * 2 + 1 > n){
if( index <= n){ //由於是先右後左，需要對只有左葉子結點而無右葉子結點的點進行特判
for(int i = 0; i < v.size(); i++)
printf("%d%s",v[i], i != v.size()-1 ? " " : "\n");
}
}
else{
v.push_back(a[index *2 + 1]); //深度遍歷右子樹
R_dfs(index * 2 + 1);
v.pop_back();
v.push_back(a[index * 2]); //深度優先遍歷左子樹
R_dfs(index * 2);
v.pop_back();
}
}
int main()
{
scanf("%d",&n);
for(int i = 1; i <= n; i++){ //這裏從i=1開始，方便後續對二叉樹有無右子樹進行判斷
scanf("%d",&a[i]);
}
v.push_back(a[1]);
R_dfs(1);
for(int i = 2; i <= n; i++){ //判斷大小頂堆
if(a[i/2] > a[i])
isMinHeap = 0;
else if(a[i/2] < a[i])
isMaxHeap = 0;
}
if(isMinHeap == 1)
printf("%s\n","Min Heap");
else
printf("%s\n",isMaxHeap == 1 ? "Max Heap" : "Not Heap");
return 0;
}