python 矩陣，列表轉換tolist()

from numpy import *

a1 =[[1,2,3],[4,5,6]] #列表
print(‘a1 :’,a1)
#(‘a1 :’, [[1, 2, 3], [4, 5, 6]])

a2 = array(a1) #列表 -----> 數組
print(‘a2 :’,a2)
#(‘a2 :’, array([[1, 2, 3],[4, 5, 6]]))

a3 = mat(a1) #列表 ----> 矩陣
print(‘a3 :’,a3)
#(‘a3 :’, matrix([[1, 2, 3],[4, 5, 6]]))

a4 = a3.tolist() #矩陣 —> 列表
print(‘a4 :’,a4)
#(‘a4 :’, [[1, 2, 3], [4, 5, 6]])

print(a1 == a4)
#True

a5 = a2.tolist() #數組 —> 列表

print(‘a5 :’,a5)
#(‘a5 :’, [[1, 2, 3], [4, 5, 6]])
print(a5 == a1)
#True

a6 = mat(a2) #數組 —> 矩陣
print(‘a6 :’,a6)
#(‘a6 :’, matrix([[1, 2, 3],[4, 5, 6]]))

print(a6 == a3)
#[[ True True True][ True True True]]

a7 = array(a3) #矩陣 —> 數組
print(‘a7 :’,a7)
#(‘a7 :’, array([[1, 2, 3],[4, 5, 6]]))
print(a7 == a2)
#[[ True True True][ True True True]]

###################################################################
a1 =[1,2,3,4,5,6] #列表
print(‘a1 :’,a1)
#(‘a1 :’, [1, 2, 3, 4, 5, 6])

a2 = array(a1) #列表 -----> 數組
print(‘a2 :’,a2)
#(‘a2 :’, array([1, 2, 3, 4, 5, 6]))

a3 = mat(a1) #列表 ----> 矩陣
print(‘a3 :’,a3)
#(‘a3 :’, matrix([[1, 2, 3, 4, 5, 6]]))

a4 = a3.tolist() #矩陣 —> 列表
print(‘a4 :’,a4)
#(‘a4 :’, [[1, 2, 3, 4, 5, 6]]) #注意！！有不同
print(a1 == a4)
#False

a8 = a3.tolist()[0] #矩陣 —> 列表
print(‘a8 :’,a8)
#(‘a8 :’, [1, 2, 3, 4, 5, 6]) #注意！！有不同
print(a1 == a8)
#True

a5 = a2.tolist() #數組 —> 列表
print(‘a5 :’,a5)
#(‘a5 :’, [1, 2, 3, 4, 5, 6])
print(a5 == a1)
#True

a6 = mat(a2) #數組 —> 矩陣
print(‘a6 :’,a6)
#(‘a6 :’, matrix([[1, 2, 3, 4, 5, 6]]))

print(a6 == a3)
#[[ True True True True True True]]

a7 = array(a3) #矩陣 —> 數組
print(‘a7 :’,a7)
#(‘a7 :’, array([[1, 2, 3, 4, 5, 6]]))
print(a7 == a2)
#[[ True True True True True True]]