[noj 1561] Set Time

簡單模擬題。這代碼長度應該還行，挺短了。

#include<iostream>
#include<cstdio>
using namespace std;

int getyear(int x)
{
	if((x%4 == 0 && x%100 != 0) || x%400 == 0)
		return 366;
	return 365;
}

int month[2][13] = {
	{31,28,31,30,31,30,31,31,30,31,30,31},
	{31,29,31,30,31,30,31,31,30,31,30,31}
};

int main()
{
	int n;
	while(~scanf("%d", &n))
	{
		int sy = 1970;
		int x = n;
		while(x >= 0)
			x -= getyear(sy++)*86400;
		printf("year: %d\n", sy-1970);
		x = n;
		int re = 0;
		sy = 1970;
		while(x >= 86400*getyear(sy))
		{
			x -= 86400*getyear(sy++);
			re += 12;
		}
		int i = 0;
		while(x >= 0)
		{
			int t = getyear(sy)-365;
			x -= month[t][i]*86400;
			i = ++i ==12 ? 0 : i;
			re++;
		}
		printf("month: %d\n", re);

		printf("day: %d\n", n / 86400 + 1);
	}
}