二叉搜索樹:左子女的值小於或等於根節點的值,右子女的值大於根節點的值。
設數據集合:data={5,4,6,3,2,1,7,9,8};
1、節點類型:
typedef struct node
{
int data;
struct node * left;
struct node * right;
}BTnode,*BTP;
2、算法:
(1)創建根節點
root=(BTP)malloc(sizeof(BTnode));
root->left =root->right =NULL;
root->data =D[0];
(2)遍歷數據集合
p=(BTP)malloc(sizeof(BTnode));
p->left =p->right =NULL;
p->data =D[i];
cu=root;
2‘查找雙親while(cu)
{
pa=cu;
if(p->data <=cu->data ) cu=cu->left ;
else cu=cu->right ;
}
3’插入節點
if(p->data <=pa->data ) pa->left =p;
else
pa->right =p;
(3)遍歷二叉樹(遞歸)
1‘前序遍歷
void Foder(BTP root)
{
if(root)
{
cout<<root->data <<endl;
Foder(root->left );
Foder(root->right );
}
}
2’中序遍歷
void Ioder(BTP root)
{
if(root)
{
Ioder(root->left );
cout<<root->data <<endl;
Ioder(root->right );
}
}
3‘後序遍歷
void Poder(BTP root)
{
if(root)
{
Poder(root->left );
Poder(root->right );
cout<<root->data <<endl;
}
}