題目鏈接:戳這裏
Common Subsequence
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42990 Accepted Submission(s): 19829
The program input is from a text file. Each data set in the file contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct. For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
題解:裸LCS,連nlogn算法都不用。
代碼:
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
int read()
{
char c;int sum=0,f=1;c=getchar();
while(c<'0' || c>'9'){if(c=='-')f=-1;c=getchar();}
while(c>='0' && c<='9'){sum=sum*10+c-'0';c=getchar();}
return sum*f;
}
char s1[1005],s2[1005];
int dp[1005][1005];
int n,m;
int main()
{
while(scanf("%s%s",s1,s2)!=EOF)
{
n=strlen(s1);m=strlen(s2);
memset(dp,0,sizeof(dp));
for(int i=1;i<n;i++)
for(int j=1;j<m;j++)
{
if(s1[i-1]==s2[j-1])
dp[i][j]=dp[i-1][j-1]+1;
else
dp[i][j]=max(dp[i-1][j],dp[i][j-1]);
}
cout<<dp[n][m]<<endl;
}
return 0;
}