在一個二維數組中(每個一維數組的長度相同),每一行都按照從左到右遞增的順序排序,每一列都按照從上到下遞增的順序排序。請完成一個函數,輸入這樣的一個二維數組和一個整數,判斷數組中是否含有該整數。
/**
* @author :Dennis
* @date :Created in 4/3/2020 21:10
* @description:
* @modified By:
* @version:
*/
public class Solution {
/**
* Plan A
* find column,then,find target by binary search
*
* @param target
* @param array
* @return
*/
public static boolean FindPlanA(int target, int[][] array) {
if (array.length == 0)
return false;
for (int i = 0; i < array.length; i++) {
if (array[i].length == 0)
return false;
if (array[i][0] > target || array[i][array[i].length - 1] < target)
continue;
//binary search
int low, mid, high;
low = 0;
high = array[i].length - 1;
while (low <= high) {
mid = low + (high - low) / 2;
if (array[i][mid] == target)
return true;
else if (array[i][mid] > target) {
high = mid - 1;
} else {
low = mid + 1;
}
}
}
return false;
}
/**
* Plan B
* find from the bottom left corner,
* if array[i][j]>target, go up
* if array[i][j]<target, go right
*
* @param target
* @param array
* @return
*/
public static boolean FindPlanB(int target, int[][] array) {
if (array.length == 0)
return false;
int i = 0;
int j = array[0].length - 1;
while (i < array.length && j >= 0) {
if (array[i][j] == target)
return true;
else if (array[i][j] > target) {
j--;
} else {
i++;
}
}
return false;
}
public static void main(String[] args) {
int[][] array = new int[4][4];
array[0] = new int[]{0, 1, 2, 3};
array[1] = new int[]{4, 5, 6, 7};
array[2] = new int[]{8, 9, 10, 11};
array[3] = new int[]{12, 13, 14, 15};
boolean stat = FindPlanB(0, array);
System.out.println("plan a:" + stat);
stat = FindPlanB(0, array);
System.out.println("plan b:" + stat);
}
}
題目地址:https://www.nowcoder.com/questionTerminal/abc3fe2ce8e146608e868a70efebf62e?orderByHotValue=1&questionTypes=000100&page=1&onlyReference=false