題目原址:點擊打開鏈接
題目描述:
Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.
Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?
For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
Note:
The input is assumed to be a 32-bit signed integer. Your function should
return 0 when the reversed integer overflows
我的代碼:
class Solution {
public:
int reverse(int x) {
long n=0;
while(x!=0){
n=n*10+x%10;
x=x/10;
}
if(n>2147483648||n<-2147483648)return 0;
return n;
}
};