572 - Oil Deposits

一道基礎的圖的歷遍的題。

思路是由一個v[][]標記當前位置是否被visit過,g[][]存儲當前是否爲pocket

每次DFS歷遍一塊deposit

主程序掃描g[][],沒發現一塊沒有被visit過的pocket,就調用DFS以它爲起點歷遍它

代碼如下：

#include<iostream>
using namespace std;

char g[110][110];
int vis[110][110];
int m, n;

void DFS(int r, int c) {
	
	//檢查邊界
	if (r < 0 || r >= m || c < 0 || c >= n)return;
	if (vis[r][c] || g[r][c] == '*')return;

	vis[r][c] = 1;
	//訪問8個方向
	for (int i = -1; i <= 1; i++)
		for (int j = -1; j <= 1; j++)
		{
			if (i == 0 && j == 0)continue;
			DFS(r + i, j + c);
		}
}
int main() {
	FILE *stream;
	freopen_s(&stream, "C:\\Users\\zgwng\\Desktop\\572OilDeposite.txt", "r", stdin);

	
	scanf_s("%d %d", &m, &n);
	char c = getchar();
	while (m != 0) {
		for (int i = 0; i < m; i++)
			gets_s(g[i]);

		int cnt = 0;
		memset(vis, 0, sizeof(vis));
		for(int i=0;i<m;i++)
			for (int j = 0; j < n; j++) 
				if (!vis[i][j] && g[i][j] == '@') {
					cnt++;
					DFS(i, j);
				}

		cout << cnt << endl;
		
		scanf_s("%d %d", &m, &n);
		char c = getchar();
	}
	return 0;
}