JavaMail實戰——內容解析，如何去除歷史內容，只收取本次內容

    這個問題不太好描述，因此還原一下場景：

    看下面的郵件，這封郵件是對之前一封郵件的回覆，因此在內容上就把之前郵件的內容也附加上了，那如果想只取本次郵件內容，該怎麼做呢？

    筆者在JavaMail API和郵件協議上都沒有找到好的解決辦法，有對郵件協議深刻了解的同學可以賜教，本文通過對內容分析，結構整理，“總結”出一套解決方案，但方案並不完美。

1. 原始內容用blockquote標籤包裹

 

實現即代碼中的remove1

2. 原始內容用includetail標籤包裹

實現即代碼中的remove2

3. 郵件初始內容是純文本不含有html標籤

實現即 代碼中的remove0

 

4. 通過與原始內容的連接點關鍵詞

如“發件人”分析連接點，去除後面的內容，實現即代碼中的remove3

 

完整代碼如下

    public String getSimpleBodyText() {
        if (this.bodyText != null) {
            return remove(bodyText);
        }
        return bodyText;
    }

    public static String remove(final String content) {
        String content0 = content;
        content0 = remove1(content0);
        content0 = remove2(content0);
        if (content.equals(content0)) {
            content0 = remove0(content0);
        }
        content0 = remove3(content0);
        return content0;
    }

    public static String remove1(String content) {
        int index1 = content.indexOf("<blockquote");
        int index2 = content.lastIndexOf("blockquote>");
        if (index1 != -1 && index2 != -1) {
            logger.debug("remove1-blockquote:" + index1 + "," + index2);
            return content.substring(0, index1) + content.substring(index2 + "blockquote>".length());
        }
        return content;
    }

    public static String remove0(String content) {
        if (!content.trim().startsWith("<")) {
            logger.debug("remove0:");
            return content.substring(0, content.indexOf("<"));
        }
        return content;
    }

    public static String remove2(String content) {
        int index1 = content.indexOf("<includetail");
        int index2 = content.lastIndexOf("includetail>");
        if (index1 != -1 && index2 != -1) {
            logger.debug("remove2-includetail:" + index1 + "," + index2);
            return content.substring(0, index1) + content.substring(index2 + "includetail>".length());
        }
        return content;
    }

    public static String remove3(String content) {
        int index1 = -1;
        int index2 = -1;
        try {
            Parser parser = new Parser(content);
            NodeFilter pFilter = new TagNameFilter("div");
            NodeList nodeList = parser.parse(pFilter);
            SimpleNodeIterator elements = nodeList.elements();
            while (elements.hasMoreNodes()) {
                Node node = elements.nextNode();
                String html = node.toHtml();
                if (node.toString().contains("WordSection1")) {
                    index2 = node.getStartPosition() + html.length();
                    continue;
                }
                if (node.toString().contains("Section1")) {
                    index2 = node.getStartPosition() + html.length();
                    continue;
                }
                if (node.toString().contains("mailContentContainer")) {
                    index2 = node.getStartPosition() + html.length();
                    continue;
                }
                if (html.contains("發件人") || html.contains("From")) {
                    if (node.getStartPosition() > 0) {
                        index1 = node.getStartPosition();
                        if (index2 == -1) {
                            if (node.getParent() != null && node.getParent().getLastChild() != null) {
                                Node lastChild = node.getParent().getLastChild();
                                index2 = lastChild.getStartPosition() + lastChild.toHtml().length();
                            }
                        }
                        break;
                    }
                }
            }
        } catch (ParserException e) {
            e.printStackTrace();
        }
        if (index1 != -1 && index2 != -1) {
            logger.debug("remove3-發件人/From:" + index1 + "," + index2);
            return content.substring(0, index1) + content.substring(index2);
        }
        return content;
    }

 

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