題目:
題解:
- 解釋一:
- 解釋二:
代碼:
public class 面試題64 {
public int res = 0;
public int sumNums(int n) {
boolean x = n > 1 && sumNums(n - 1) > 0;
res += n;
return res;
}
public static void main(String[] args) {
int n = 9;
面試題64 test = new 面試題64();
int res = test.sumNums(n);
System.out.println(res);
}
}